Explain resolution of vectors.
In figure (a), $\vec{A}$ and $\vec{B}$ vectors are coplanar and non-parallel.
$\overrightarrow{\mathrm{R}}$ is to be resolved in $\overrightarrow{\mathrm{A}}$ and $\overrightarrow{\mathrm{B}}$
Suppose, $\overrightarrow{O Q}$ represent $\vec{R}$
In figure (b), draw a line parallel to $\vec{A}$ from $O$ and draw another line parallel to $\vec{B}$ passes through Q. Both lines intersect at P.
As per triangle method for vector addition,
$\overrightarrow{\mathrm{OQ}}=\overrightarrow{\mathrm{OP}}+\overrightarrow{\mathrm{PQ}}$
Here, $\overrightarrow{\mathrm{OP}} \| \overrightarrow{\mathrm{A}} \quad \therefore \overrightarrow{\mathrm{OP}}=\lambda \overrightarrow{\mathrm{A}}$
and $\overrightarrow{\mathrm{PQ}} \| \overrightarrow{\mathrm{B}} \quad \therefore \overrightarrow{\mathrm{PQ}}=\mu \overrightarrow{\mathrm{B}}$
(Here, $\lambda$ and $\mu$ are scaler values)
$\therefore \overrightarrow{\mathrm{R}}=\lambda \overrightarrow{\mathrm{A}}+\mu \overrightarrow{\mathrm{B}}$
OR
$\overrightarrow{\mathrm{R}}=($ Component of $\overrightarrow{\mathrm{R}}$ in direction of $\overrightarrow{\mathrm{A}})+($ Component of $\overrightarrow{\mathrm{R}}$ in direction of $\overrightarrow{\mathrm{B}})$
A particle starting from the origin $(0,0)$ moves in a straight line in the $(x, y)$ plane. Its coordinates at a later time are $(\sqrt 3,3)$ . The path of the particle makes with the $x -$ axis an angle of ....... $^o$
Three forces acting on a body are shown in the figure. To have the resultant force only along the $y-$ direction, the magnitude of the minimum additional force needed is ........... $N$
Two vectors of magnitude $3$ & $4$ have resultant which make angle $\alpha$ & $\beta$ respectively with them $\{given\, \alpha + \beta \neq 90^o\}$