Explain the resolution of vectors.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) In figure $(a)$,$\vec{A}$ and $\vec{B}$ are coplanar and non-parallel vectors.
We want to resolve vector $\vec{R}$ into components along $\vec{A}$ and $\vec{B}$.
Suppose $\vec{OQ}$ represents $\vec{R}$.
In figure $(b)$,draw a line through $O$ parallel to $\vec{A}$ and another line through $Q$ parallel to $\vec{B}$. These two lines intersect at point $P$.
According to the triangle law of vector addition:
$\vec{OQ} = \vec{OP} + \vec{PQ}$
Since $\vec{OP} \parallel \vec{A}$,we can write $\vec{OP} = \lambda \vec{A}$.
Since $\vec{PQ} \parallel \vec{B}$,we can write $\vec{PQ} = \mu \vec{B}$.
(Here,$\lambda$ and $\mu$ are scalar constants).
Therefore,$\vec{R} = \lambda \vec{A} + \mu \vec{B}$.
This means $\vec{R}$ is expressed as the sum of its components in the directions of $\vec{A}$ and $\vec{B}$.

Explore More

Similar Questions

Three vectors $\overrightarrow{OP}, \overrightarrow{OQ}$ and $\overrightarrow{OR}$ each of magnitude $A$ are acting as shown in the figure. The resultant of the three vectors is $A \sqrt{x}$. The value of $x$ is:

If $\vec{A} = \hat{i} A \cos \theta + \hat{j} A \sin \theta$ is a vector,then another vector $\vec{B}$ which is perpendicular to $\vec{A}$ is given by:

The $x$-component of the resultant of several vectors is:

What is the maximum number of rectangular components into which a vector can be split in space?

The magnitude of vectors $\overrightarrow{ OA }, \overrightarrow{ OB }$ and $\overrightarrow{ OC }$ in the given figure are equal. The direction of $\overrightarrow{ OA }+\overrightarrow{ OB }-\overrightarrow{ OC }$ with the $x$-axis will be

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo